題:
數學-代數
Theresa
2006-10-13 21:39:21 UTC
7K-(9K-16)=14-(19-K) 求K (請詳細解答)

2/3(3b+2)-1/6(3b-1)=-1/1/2 求B (請詳細解答)
六 答案:
?
2006-10-13 21:50:47 UTC
7K-(9K-16)=14-(19-K) 求K

16-2K=K-5

3K=21

K=7



2/3(3b+2)-1/6(3b-1)=-1/1/2 求B

2b+4/3-1/2b+1/6=-1/1/2

1/1/2b=-3

b=-2



你對下個ans.~睇下啱唔啱

希望幫到你 ^ v ^
鳳愛
2006-10-13 21:59:11 UTC
7K-(9K-16)=14-(19-K)

7K-9K+16=14-19+K

7K-9K-K=14-19-16

-3K=-21

K=7







2/3(3b+2)-1/6(3b-1)=-1/1/2

2b+4/3-b/2+1/6=-2

2b-b/2=-2-4/3-1/6

12b-3b=-12-8-1

9b=-21

b=-21/9

b=-7/3
?
2006-10-13 21:48:08 UTC
1.

7K-(9K-16)=14-(19-K)

7K-9K+16 =14-19+K

7K-9K+16+19=14-19+K+19

-2K+35-14=14+K-14

-2K+21=K

3K/3=21/3

K=7

2.

不懂
Angus
2006-10-13 21:46:43 UTC
7K-(9K-16)=14-(19-K)

7K-9K+16=14-19+K

-2k-K=-5-16

-3K=-21

K=7



第二題個右邊係-1除1/2定-1/1除2 ?

左邊係2除3(3b+2)定係2(3b+2)除3??
hoi yi
2006-10-13 21:44:23 UTC
7K-(9K-16)=14-(19-K)

7K-9K+16=14-19+K

-2K+16= -5+K

21=3K

K=9



2006-10-13 21:45:07 補充：

K=7吾係=9
?
2006-10-13 21:44:18 UTC
7K-(9K-16)=14-(19-K)

7K-9K+16=14-19+K

-2K + 16 = -5+K

-2K-K = -5-16

-3K = -21

K = 7



2/3(3b+2)-1/6(3b-1)=-1/1/2??

疑問→(3b+2)係乘去分子定係分母呢

仲有，(3b-1)又係乘寺分子定係分母呢



你補充番先啦


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